Nailed it, guys, thanks. I need to add that one to my toolbox. I've seen it before.
Got to give it a name of some sort. The chains have the same spacing, but because values in the chain are in the same category, we can eliminate the equality of their related links. Both chains begin from different points in the same category and head in the same direction at the same pace. Uneven Parallel Chains?
Ax + c = Jm
Ay + c = Kn
Jm <> Kn
CategoryAindexx, plus some constant, c, equals CategoryJindexm
CategoryAindexy, plus some constant, c, equals CateogryKindexn
Implies that CategoryJindexm cannot be CategoryKindexn
Where c is the same in both equations
Where CategoryJ or CategoryK can equal CategoryA (but not both because the problem would be easy to solve)
Where all four values Ax, Ay, Jm, Kn represent four distinct values.
