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12-30-2013, 03:57 PM
 riverfloat45 Junior Member Join Date: Nov 2013 Location: USA Posts: 5
Cannot solve common logic conundrum

Hello from a new, self-taught solver. I have progressed to moderate level and am stuck wrapping my mind around a common puzzle situation. The hint is not detailed enough for this stuck mind! I do not use hints normally, but I keep running into this wall and thought the hint would help as a guide.

The puzzle reference number: Puzzle #540475

The logic:
Of the diner who paid \$4.99 and Lee, one ordered the hamburger and the other had the iced tea.

The hint:
If Lee does not equal \$6.99, and hamburger and iced tea can only be paired with either \$4.99 or Lee, then hamburger cannot be equal to \$6.99. Mark the highlighted cell as FALSE. I am noting that both iced tea and hamburger were available for Lee at this time, as well as both available for \$4.99 and \$6.99.

Can someone please explain, in layman's terms, why this must be so? In my apparently stubborn mind, why cannot Lee have been the iced tea, therefore still allowing the hamburger for \$6.99? I am aware this is an awkward explanation of my problem.
Any help is most appreciated.

Last edited by riverfloat45; 12-30-2013 at 03:59 PM. Reason: poor grammar