View Full Version : I see the solution, but what's the logic?

BillsBayou

06-17-2013, 08:34 PM

Here's the blank:

86

And here's the bottleneck:

87

If you replace mushroom with Fusilli, clues 1 and 5 reduce to just two categories:

Yolanda plus $1 is Capellini

Fusilli plus $1 is Angie

With:

Angie not Yolanda

Fusilli not Capellini

Angie not Capellini

Yolanda not Capellini

I worked it out that this cannot happen:

Angie is $9.99

Fusilli is $8.99

Leaving Yolanda to be either:

Yolanda is $7.99, but Capellini cannot be $8.99 (already taken)

Yolanda is $8.99, but Capellini cannot be $9.99 (Angie cannot be Capellini)

So, Angie must be $8.99, and she is, and everything falls into place.

BUT WHAT IS THE LOGIC beyond the bottleneck? I don't see it. How do I frame what's left into a logical statement?

shriekingviolet

06-17-2013, 09:30 PM

Yikes, this one is tricky. Hopefully this will make sense.

Clue 5 - Angie is $1 more than the mushroom sauce. So either $7.99=mushroom/$8.99=Angie -OR- $8.99=mushroom/$9.99=Angie. So either way, $8.99 must be Angie or whoever had the mushroom sauce (either Wade or Yolanda), so you can eliminate Margie from $8.99.

Therefore you can eliminate $8.99 from capellini

After that, go back to clue 1 and you can now eliminate $7.99 from Yolanda

So now, from clue 1 again, but substituting Margie for capellini: $8.99=Yolanda/$9.99=Margie or $9.99=Yolanda/$10.99=Margie. So $9.99 must be either Margie or Yolanda, which leaves Angie at $8.99

zenobia43

06-18-2013, 12:57 AM

And here is yet another method using the two ordering clues with a substitution.

Lay out clues 1 and 5 with the substitution for capellini.

Yolanda -> capellini = Margie

mushroom -> Angie

Notice that Margie and Angie are in the same category, same side of the relation, and a fixed distance from the left side.

That means Yolanda cannot be mushroom. Wade must be mushroom.

Shriekingviolet has a more interesting approach, and it demonstrates how the one-sided "Of A and B, one is C and the other is D" clue can yield extra Xs beside the obvious one.

"A is either C or D" is very similar to its two-sided cousin. Just find out what C and D can never be, and apply those exclusions to A.

As SV points out, from the partial solution grid, $8.99 is either Angie or mushroom. From the grid, we see that the intersection of Angie and mushroom also has four Xs that can be applied to $8.99. One of these Xs is "$8.99 cannot be Margie."

BillsBayou

06-18-2013, 03:52 PM

Thanks to ShriekingViolet and Zenobia43 for laying this out. Yet another technique learned, here.

I'm working up a graphic to explain it all for anyone who doesn't see it. I'll link to it here in a few minutes.

Zenobia43, it looks like I still need work on my approach to multiple fixed-relational clues that use the same category. That would have solved it for me.

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